- Birthday Grapher has been discontinued
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Developer
Brian Flanagan
Birthday Grapher helps users discover the Birthday Paradox. Like many people, when I was first introduced probability's infamous "Birthday Paradox" I was in strong disbelief. I saw the formula and accepted it, but never really got it.
Recently I decided to convince myself of the validity of the paradox through the creation of a simple computer program. What this program does is takes a test-pool (or what I call a "room") and for each "person" in the "room" picks a number from 1 to 365. Then it checks to see if there are any duplicate numbers and returns "1" if there are and "0" if
Recently I decided to convince myself of the validity of the paradox through the creation of a simple computer program. What this program does is takes a test-pool (or what I call a "room") and for each "person" in the "room" picks a number from 1 to 365. Then it checks to see if there are any duplicate numbers and returns "1" if there are and "0" if
What's New
Version 1.3:
- Fixed minor memory issues.
Requirements
PPC, Mac OS X 10.3 or later
PPC, Mac OS X 10.3 or later
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| Downloads:3,910 |
| Version Downloads:2,505 |
| Type:Education : Mathematics |
| License:Free |
| Date:21 Jan 2006 |
| Platform:PPC 32 / OS X |
| Price:Free |
Overall (Version 1.x): |
| Features: |
| Ease of Use: |
| Value: |
| Stability: |
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Birthday Grapher helps users discover the Birthday Paradox. Like many people, when I was first introduced probability's infamous "Birthday Paradox" I was in strong disbelief. I saw the formula and accepted it, but never really got it.
Recently I decided to convince myself of the validity of the paradox through the creation of a simple computer program. What this program does is takes a test-pool (or what I call a "room") and for each "person" in the "room" picks a number from 1 to 365. Then it checks to see if there are any duplicate numbers and returns "1" if there are and "0" if there aren't. Then it repeats this process a user specified number of times until it finally averages all of the ones and zeros together to produce a probability.
For the fun of it, I decided to have the program graph whole ranges of room-sizes to show the really unintuitive behavior of this problem.This program doesn't do much, but it does what it says it will pretty well. It's worth taking a look at.
Recently I decided to convince myself of the validity of the paradox through the creation of a simple computer program. What this program does is takes a test-pool (or what I call a "room") and for each "person" in the "room" picks a number from 1 to 365. Then it checks to see if there are any duplicate numbers and returns "1" if there are and "0" if there aren't. Then it repeats this process a user specified number of times until it finally averages all of the ones and zeros together to produce a probability.
For the fun of it, I decided to have the program graph whole ranges of room-sizes to show the really unintuitive behavior of this problem.This program doesn't do much, but it does what it says it will pretty well. It's worth taking a look at.
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